Test:108 QNo:7

A stone thrown upwards with a velocity v from the top of the tower reaches the bottom of the tower at speed n×v. What is the height of the tower?

3 Answers

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the height will be equal to v²(n²-1)/2g

using the thrid equation of motion, and taking downwards as negative and upwards as positive.
we get,
(nv)² = v² - 2g(-h)
or, h = [(nv)² - v²]/2g.

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