3i tried equating potential,but could not proceed, please help
two conducting spheres of radii r1 and r2 have charge q1 and q2 respectively.after bringing them in contact,what happens to the energy of the system?
a)no change
b)increase if q1r2≠q2r1
c)decrease always
d)decrease if q1r2≠q2r1
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2 Answers
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1161Energy will always decrease. Since there will be flow of charge from lower potential to higher potential and in that flow energy will be lost in form of heat.
In general formula for that loss of energy is:
ΔU=C1C22(C1+C2)(V1-V2)2
- K. R. Ramakrishna but sir, answer given is d...i dont understand why.....Upvote·0· Reply ·2014-06-20 03:27:03
- Akash Anand Because in that condition (d) only the potential will be different and flow of charge will take place.