electrostats

The conducting, concentric , hollow spheres A and B have radii a and b
respectively, with A inside B. Their common potential is V. A is now given some charge such that its potential becomes zero. The potential of B now will be ????????????

7 Answers

62
Lokesh Verma ·

dude.. i could not figure the exact set up of this question..

could u explain it again?

1
big looser ......... ·

i have posted complete question. its from d.c pandey.
no other information is given in question

1
big looser ......... ·

ans is V(b-a)/b

1
big looser ......... ·

integration ,, i have already posted the answer

62
Lokesh Verma ·

EDITED TO CORRECT MY MISTAKE

wanst that unclear.. sorry dude.. just was not in my mind :)

let charges be q on inner and r on outer shell

kq/b+kr/b=kq/a +kr/b = V
=>q=0!

so kr/b=V
if we earth it or make potential at "a" zero, then let q1 flow to it..

potential at a will be kq1/a+kr/b = 0

q1=-r.a/b

so potential at b will be

kq1/b + kr/b =

-kra/b2+kr/b

kr/b{-a/b+1}

V(1-a/b)

=V(b-a)/b

1
big looser ......... ·

i think The potential on inner shell is kq/a + kr/b

62
Lokesh Verma ·

sorry dude u are right.. i made a stupid damn mistake last nite.. i think i needed more sleep [1]

Now i hope this is correct .. just check it...

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