EMI-1

Sir how to approach.

2 Answers

591

Akshay Ginodia ·2013-08-29 02:57:25

At any time 't' let the velocity be 'v'
then E=Blv
and charge on capacitor Q=CE= cBlv
Current(i)= dQ/dt = dclBv/dt = clB dv/dt = clBa

Now mg-ilB= ma
or, mg-clBa*lB=ma
or, a(m+cl²B²) = mg
so, a = mg/m+cl²B²

Is this the answer???

1161

Akash Anand ·2013-08-29 06:10:52

Will do this kind of question in next class..till that time keep trying.

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