Daily Graph 17-06-11

@satyajit,
notice that due to the |x| , |y| the graph will be symmetrical in all the 4 quadrants.
and another point to note is that 1 - [|x|] cannot be negative since box of a positive number (|y| ) has to be positive.
so the geaph is bounded between x = -2 and +2 and same for y.

now take cases;
case1: 0≤ x < 1
[x] = 0

case2: 1≤x<2
[x] = 1.

using this draw the graph in first quadrant and replicate to other quad.

btw, nishant sir and all other bhaiyas why dont you continue this thread by posting questions like graph of the week
this will also save your time and be a good revesion tool for us.

nishant sir,can you please explain asish's solution of the second graph?

@nishant sir ,

this is not true

i drew the graphs of y=1/x
y=1.1/x
y=1.2/x
.
.
.

y=2/x

using software

for the advantage of the students here to understand it clearly
and super imposed these graphs

and fyi ,no graph making software can make graphs of [x] and {x}

i thought you could have understood it

leaving all these behind ...
lets us focus back on some intellectual stuff

can we calculate the area ???

although i was deeply hurt by your allegations

bhaiya is this oen right ??

1 ≤ x y < 2

So , a number of hyperbolas , what else ?

Won't there be more curves in the third quadrant as well?

to the original question

What a feeling to have got a pink in this legendary section of GODs! [3]

Is ricky bhaiya's graph like this :

From, y=2 onwards, there will no value of x which will satisfy the given equation.. so the graph.. [1]

Another graph -

[ | y | ] = 1 - [ | x | ]