x=0;
if k is infinite smaller value and then x can be a greater value such that kx→0
x=0;
if k is infinite smaller value and then x can be a greater value such that kx→0
x=0 is only solution why are u bothering abt x→0 ??
then kx→sinkx but not exactly equal
celestine your answer is almost 100% correct
you only missed out the case when k=0 :P