Fluids-2 (Jee Mains-2014)

4 Answers

865
Soumyadeep Basu ·

I did this by playing with the options. Putting α=0, options 2 and 4 can be eliminated. Now, if α=45°, then it means that d2=0, as COM of liquid d1 would then be at the lowest point. That leaves us with option 3 as the answer.

158
Anik Chatterjee ·

take the point of intersection of the liquids...let it be A..take another point at the same horizontal level(on other side of tube)..let it be B..
now PA=PB..(same horizontal level)
P0+d1gh1=P0+d2gh2
now h1=Rcosα-Rsinα
&h2=Rcosα+Rsinα(h1,h2 is found using the fact that both of them subtend a right angle at the centre..)
this gives...(c) as the answer..

1161
Akash Anand ·

535
Aditya Agarwal ·

Sir, is the tube accelerating towards the left?
Otherwise how can we get such a slanting surface?

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