1got it back!! [1]
two blocks A and B of mass M and 2M are connected by a string of length 3L. The block B is released from the position shown. When the string is just taut, the velocities of blocks and impulse tension in the string will be ??
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6 Answers
62this is not very tough.. but not very easy either..
See what will happen after the string just goes down to the exact length 2l?
The string will apply imipulse on both the blocks... Equal in magnitude!!
Hence it will be like a collision.. without ur realising it :O
1why would the velocities of the blocks not be √4gl/3?
would the energy b conserved
62the velocity when it just is about to make the string taut is
√2gH= √2g.2l = 2√gl
after collision it will be
2√gl.m = 3mv
v= 2/3√gl
I din understand ur logic of saying why it should have been the value u put it at?!
1sorry the 3 came inside the root
but i was thinking why should we not take tension as an external force