Kinematics-13

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A train starts from a station with a constant acceleration of 0.4 m/s². A passenger arrives at a station 6 s after the end of the train left the very same point. What is the least speed at which the passenger should run to catch the train?

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1133

Sourish Ghosh ·2013-06-12 07:33:34

4.8m/s

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Akash Anand Try to give a crisp solution at the end of the day.
Upvote·0· Reply ·2013-06-12 23:33:20
Akash Anand Excellent work
Upvote·0· Reply ·2013-06-12 23:33:30
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1133

Sourish Ghosh ·2013-06-13 07:45:22

12at² = v(t-6)

Apply conditions for minima, get value of 't' and then find v accordingly.

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Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Kinematics-13

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