Laws of Motion-12

8 Answers

1161
Akash Anand ·

996
Swarna Kamal Dhyawala ·

(A)

66
Soumyadeep Chatterjee ·

A

466
Himanshu Giria ·

A

466
Himanshu Giria ·

A → T → x
B → 2T → y
Tx + 2Ty = 0
x+2y =0
a1 = -2a2 .......( i )
T - 4g = 4a1 .......( ii )
T - 5g = 5a2 .......( iii )
Solving we get :

a1 = -2g / 7
and a2 = g / 7

49
Pratyasha Das ·

Let the acceleration for block A be a1 downwards and that for B be a2 upwards.
so,A→T→-x
B→2T→Y
-Tx+2Ty=0
x=2y
a1=2a2
now,4g-T=4a1
8g-2T=8a1=8(2a2)=16a2....(1)

2T-5g=a2....(2)
(1)+(2)
3g=17a2
a2=3g/17
a1=6g/17
SO THE ANSWER SHOULD BE NONE OF THIS i.e. (D)

535
Aditya Agarwal ·

is the answer (d)?

535
Aditya Agarwal ·

accln A = g/9 downward
accln B = g/18 upward

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