a=F/m(cosθ-sinθ)-μg
- Sahil Jain please explain howw
Upvote·0· Reply ·2013-08-05 21:48:58
A body of mass m slides down a horizontal plane asit is pushed by aforce F which makes an angle θ with the horizontal.sow that the normal force acting on the body is given by N = mg + Fsinθ.Find the acceleration in terms of F and μk.
a=F/m(cosθ-sinθ)-μg
It should be N= mg- Fsinθ
N upward, mg downward and F sinθ upwards, so the F.B.E.
looks like this:
N + Fsinθ = mg
=> N= mg- Fsinθ
Where did you find this question? (o.O)
And how can something slide down a horizonal plane?; it can slide along a horizontal plane, I find the question quite confusing!
Aniq is r8......d first part of d question is wrong..........N=mg-Fsin@
And Pratyasha gave d r8 answer of d 2nd part......
fcosa in x direction and fsin(a) in y direction SO
W=mg
N= w+fsin(a)
N= mg + fsin(a)
now,
uk(N)=m.a
uk(mg+fsina)/m=a