# Laws of motion

A body of mass m slides down a horizontal plane asit is pushed by aforce F which makes an angle θ with the horizontal.sow that the normal force acting on the body is given by N = mg + Fsinθ.Find the acceleration in terms of F and μk.

## 6 Answers

49
Pratyasha Das ·

a=F/m(cosθ-sinθ)-μg

• Sahil Jain please explain howw
51
Aniq Ur Rahman ·

It should be N= mg- Fsinθ
N upward, mg downward and F sinθ upwards, so the F.B.E.
looks like this:
N + Fsinθ = mg
=> N= mg- Fsinθ

Where did you find this question? (o.O)

• Aniq Ur Rahman And if u mean that the force is making an angle theta with the horizontal, you should've mentioned "clockwise direction". The word DOWN has no practical meaning. :D XD
51
Aniq Ur Rahman ·

And how can something slide down a horizonal plane?; it can slide along a horizontal plane, I find the question quite confusing!

481
Anurag Ghosh ·

Aniq is r8......d first part of d question is wrong..........N=mg-Fsin@
And Pratyasha gave d r8 answer of d 2nd part......

466
Himanshu Giria ·

WHAT is the meaning of asit ?

• Sagnik Kar it will be "as it"
283
Sahil Jain ·

fcosa in x direction and fsin(a) in y direction SO
W=mg
N= w+fsin(a)
N= mg + fsin(a)
now,
uk(N)=m.a
uk(mg+fsina)/m=a

• Sahil Jain instead of theta i used a ..:-) doesn't matter :-P
• Himanshu Giria plz show how did u get the 2nd last line ?
• Sahil Jain soorry i frgt Fcos(A)