Laws of motion

T1=16N and T2=32N

how?

When all the blocks are taken at a time we get,

F-2gsin(30°)+2gsin(30°)+gsin(30°)=2a+2a+a

→ 5a = 40-25
→ a = 3m/s²
If we consider the 1st block (the one only joined to T1),

T1 - 2gsin(30°) = 2a

→T1=16N

Now consider the block being pulled by F,

F-T2-gsin(30°) = a

→T2 = F-(g/2)-a = 32N

You could also had considered the middle block.In that case the equation would be,

T2-T1-2gsin(30°)=2a