max h

writing energy conservation..

mg2R=1/2mv²+mgR(1+cosθ)......

balancing force where it will leave the surface..

mg.cosθ=mv²/R...

From two equations..

cosθ=2/3

so it will leave surface at a height of R(1+cosθ)=5R/3

with velocity.. v=√2gR/3
in the direction shown below..

velocity is making θ with horizintal...
thereafter parabolic path so max ht there is say h

Hence the answer..

:)

yes in these not 75% but 95% one get this and in friction tan^-1μ

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