1Dear DareDev
You are wrong.The answer I have is m(a2+b2)3.Please try again.
Derive the moment of inertia of a rectangular plate having sides a and b about an axis passing through one end and perpendicular to the plate.
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8 Answers
1hey consider a rod of length a....the moi abot itzz centre perpndclr....iz mlsquare by 12.........apply parallel axis theorem
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21how they derived in case of a rod?
proceeding in the similar way we can find the MI of the rectangular plate wrt a axis perpendicular to the plane of the rectangle which is at right angle with the side "a"
let it be Ix
Ix will be equal to ma212
similarly Iy = mb212
so Iz = Ix + Iy
now using parallel axis theorem shift the axis to a distance equal to half of the length of the diagonal of the rectangle ;)
1The answer is M(a2+b2)/3 if we find the MI about an axis passing through a corner perpendicular to the plane . We have MI=Ma2/12+Mb2/12+M(√(a/2)2+(b/2)2)2 =M(a2+b2)/3
1U ARE JUST TOO UNCLEAR WE HV TO FIND ABOT CORNER........OR THE CENTRE OF SIDE....U ALWAYS CREATE HORRIBLE CONFUSIONS