1i ll solve it tomorrow (try to)
ABCD is a track in the vertical plane AB and CD being smooth and concave upwards BC being an inclined plane with μs=0.3 , μk=0.2 and θ=tan-11/4. horizontal dist b/w B and C is 2 metres.
if the particle is released from rest at A find the horizontal distance between B and the point where it comes to rest.
vertical ht between B & A is 4.3 metres
A is above B and D is above A of course
dumb hint-
use energy conservation in path AB and CD
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UP 0 DOWN 0 0 7
7 Answers
1no one yet so there are the options
a)0
b)1/3
c)2/3
d)3/2
in metres all of them
1are AB & CD both concave upward????
is mass not required?????
cant get the fig currently
1no mass not reqd.
ab and cd smooth so their slope doesn.t matter jus use energy conservation
point a above b and b is the lower point of inclined plane
hotspot in the question is the part bc the inclined plane
1ya im trying to upload the image but its not going
see if anyone of you can do it if its clear to you