nice question...........lets see who solves it first correctly....

Two point masses m1 and m2 are connected by a spring of natural length l.The spring is compressed such that two point masses touch each other and then they are fastened by a string.Then system is moved with velocity v along the +ve X axis.When the system reached the origin the string breaks (t=0).The position of point mas m1 is given by x1=vt-A(1-cos #t) where A and # are constants.

Find position of second block as a function of time.Also find relation between A and l

1 Answers

1357
Manish Shankar ·

x2 should move such that the centre of mass moves through distance vt

(m1x1+m2x2)/(m1+m2)=vt

m2x2=(m1+m2)vt -m1x1=m1vt+m2vt - m1(vt-A(1-cos#t))
=m2vt +m1A(1-cos#t)

x2=vt + (m1/m2)A(1-cos#t)

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