physics problem

11 Answers

1
rishabh ·

160 π2 cos(4πt)7 ?

71
Vivek @ Born this Way ·

Nopes!
Approach pleasE?

1
rishabh ·

acc. of platform = - 32 π2 cos(4πt)
=> pseudo force on sphere = 32 π2 cos(4πt)
force eqn. of sphere => 32 π2 cos(4πt) - f = ma
torque eqn. => f.R = 2/5 mR^2 α
a = Rα
solving gives tht answer

71
Vivek @ Born this Way ·

Ohh. I misread the problem. thanks!

1
rishabh ·

what's the answer?

71
Vivek @ Born this Way ·

- 32/3 π2 cos(4πt)

1
rishabh ·

what is wrong in my soln. ?

21
Swaraj Dalmia ·

MI of a cylinder =MR2/2

1
rishabh ·

lol! read sphere :P

71
Vivek @ Born this Way ·

Does that give correct answer.Don't know wherefrom I'm getting an extra 2 in numerator

1
Manoj Srivastava ·

Hi all, get relevant and useful flash animations in physics at http://www.mksfoundation.com/flashlets.aspx
and lot of other free stuff for JEE preparation at this site.

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