projectile

a projectile will cover the maximum vertical distance in the minimum time when the angle of its projection with the horizontal is

i know the ans is 45° but i am not able to prove it

2 Answers

62
Lokesh Verma ·

karan the proof is relatively simple...

the time for which the projectile remains in the air is given by

2usinθ/g

The horizontal velocity is u cosθ

The range is horizontal velocity times "time"

so it is 2u2sinθ.cosθ/g

=u2sin2θ/g

for maxima sin 2θ=1

so θ=45 degreees :)

1
Pavithra Ramamoorthy ·

DIS ONE S A STD PROOF N SIMPLE TOO.....

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