परिपत्र गति

√5√2gl ??? guessing :P

Why theres no topic [3]

http://targetiit.com/iit_jee_forum/posts/no_topic_1407.html

i think because of that hindi titile [4]

okie u r8...

i took a wrong equilibrium position :P

So final answer is..
√gl(3√2+2)

above picture is rotated 45° clockwise.. :P

Now v is to be found out..

1/2mv²+m√2gl(1-1/√2)=1/2m(5√2gl)

[7]

1/2mv² - 1/2m (5√2gl) = mgl(1-cos45°)

question achha hai :)

no.. not the correct answer :)

How did you get √5gl?

so whats the min velocity imparted at position shown so that it just completes the circle..

hint is in ur reply [1] or solve subjectively [1]