two forces F1 and F2 are applied on spool of mass M and moment of inertia I about an axis passing from centre of mass.Find the ratio F1/F2 so that force of friction is zero. Given I<Mr2
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1 Answers
62a = (F1+F2)/m
FOr pure rotation,
a=α.(2r)
α = (F1+F2)/2mr
F1.2r-F2.r = Iα
(F1+F2)/2mr = F1.2r-F2.r
divide by F2 on both sides
F1/F2 + 1 = (2F1/F2 - 1) 2 m r2
F1/F2 = {1+ 2 m r2}/{4 m r2 - 1 }
Make sure there are no calculation errors!!
