Rotation

4 Answers

865
Soumyadeep Basu ·

Yes, I had been making a mistake.
Consider the ring with the point mass as the system. The net force acting on it is 2mg-N at the time of release. Now, 2mg-N=2maCOM. From the centre of the ring, the only torque is Rmg acting on the point mass. Now, Rmg=Iα=2mR2α ie g=2Rα.
The centre of mass is always at the mid-point of the centre of the ring and the position of the point mass. So, aCOM=R2α.
From this, we can get the value of N as 32mg.

865
Soumyadeep Basu ·

0.4g?

865
Soumyadeep Basu ·

No, it will be 43mg. Is it correct now?

1
Soumyadip Kundu ·

Assume that a geosynchronous communications sattelite is in orbit at kolkata [latitude 28°]you are in kolkata and want to pick it signals. In what direction should you point the axis of the parabolic antena?

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