SHM

CHECK THIS OUT......

and let me know the solution....

15 Answers

1
prateek punj ·

c'mon guys.....

1
prateek punj ·

ans it....

33
Abhishek Priyam ·

time period is =2pi√Ip/mgl

where l is distance of COM of the setup from hinge and Ip is moment of inertia about the hinge..

:)

1
prateek punj ·

please can u give me the solution...
becoz i have tried all the formulaes....
but still i was not able to get the ans....

33
Abhishek Priyam ·

Ok :)

33
Abhishek Priyam ·

time period is straight forward...

here l=mR/(M+m)

mass =M+m

Ip=MR2/2+mr2/2+mR2

Put these in the formula(that formula is for every setup hanging be it cone, triangle, circle, or any compound structure..)

Tell me if u can't understand any term in what i have written in Ip or any other..

:)

and for velocity write energy conservations..
If u want i will post a bit on it also

:)

1
prateek punj ·

yeah buddy...
please post the solution for veloc. also...

33
Abhishek Priyam ·

okie.. :)

mgl(1-cosθ)=1/2Ipw2

velocity of com of smaller disc=wR

Put l and Ip from above and let me know if answer is coming or not otherwise i will solve it..

1
prateek punj ·

hey in this case l will be equal to R....
and not the above value

1
prateek punj ·

i was not taking the value of I correctly....
thats why my ans was varying....
thanx a lot buddy....

33
Abhishek Priyam ·

no..

but one mistake.. m is total mass M+m and l is the one above mentioned there

(M+m)gl(1-cosθ)=.....

1
prateek punj ·

but dude with that the ans will be wrong....it will be only m....
bcoz there will only be change in the potential energy of C.O.M of small disc..... and not the bigger disc....

33
Abhishek Priyam ·

sorry :P

question hi bhoola gaye the

yes l=R and m=m

but RHS is right..

:)

1
prateek punj ·

chalo thanx for all ur help....

33
Abhishek Priyam ·

:)

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