speeeed

A uniform spherical shell of mass M rotates about vertical axis on frictionless bearings.A light cord passes around the equator of the shell over a masssless pulley and attached to block(mass m) which is otherwise free to fall under gravity.What is speed of object after it has fallen distance h from rest

8 Answers

1
°ღ•๓яυΠ·

mgh=1/2(Iw^2) +1/2mv^2

I=2/3mr^2

24
eureka123 ·

I dont get answer form here......do u get √[2gh]/[1+(2M/3m)]???????

1
°ღ•๓яυΠ·

wait will do it on paper n then tell

1
°ღ•๓яυΠ·

yeah .........u get just take I as 2/3Mr^2 itz a hollw sphere

cheers~

24
eureka123 ·

but i am not getting it........

1
°ღ•๓яυΠ·

2mgh=2/3Mr^2 w^2+mv^2
v=wr
so u get

2mgh=2/3Mv^2+mv^2
so nw u hav

2mgh/(2/3M+m)=v^2
dividin thruout by m u get
2gh/((2M/3m)+1) =v^2
then take d root
:)

24
eureka123 ·

shit........silly mistake.......
i was writing 2mgh=2/3mv^2+mv^2 !!!!!!!!!!!!!!!!!!!!

anyways thanxxxxx

1
°ღ•๓яυΠ·

hota hai hota hai..........:)
dnt study .......so mush ;P

Your Answer

Close [X]