work and power

AIEEE 2015 Papers › Mechanics questions › work and power

a chain of mass m=0.8 kg and length l=1.5 m rests on a rough table so that one of its ends hangs over the edge.The chain starts sliding off the table all by itself provided the hanging part is n=1/3 of chain's length.What will be the total work done by the frictional forces acting on the chain by the moment it completely slides off the table?

#Physics #Mechanics

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7 Answers

213

Nandikesh Singh ·2014-01-22 03:06:57

-7mgl/18 J
=4.66 J

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213

Nandikesh Singh ·2014-01-22 03:07:41

= -4.66 J

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466

Himanshu Giria ·2014-01-22 03:38:33

plz shw how

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283

Sahil Jain ·2014-01-22 08:15:45

P.e (i)= -Mgl/18
Pe (f) = -Mgl/2
According to law of energy con
Work done is= pe(i) - pe(f)
=-8mgl/18=-5.333

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1161

Akash Anand ·2014-01-29 03:34:31

I guess the answer would be -1.34 J.

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213

Nandikesh Singh ·2014-01-31 05:40:13

how?

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1161

Akash Anand ·2014-02-12 06:04:35

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Your Answer

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