3/T
PT2=constant
from ideal gas eqn T3/V= contant
dV/VdT=3/T
3/T
PT2=constant
from ideal gas eqn T3/V= contant
dV/VdT=3/T
sir i did it dis way
T3/V = constant
soo
T13 /V1 = T23/V2
and V2 = V1 (1+r (T2 - T 1))
ON SOLVIN
r = (T12 + T22 + T1T2 )/T23
AND REPLACIN T1 AND T2 AS T
WE GT r=3/T
you have got the answer but i am afraid this is not the right method....
you have to do it from the first principle which abhirup used..
thsi one worked for this question but will fail for many many other questions!
sir can u pls xplain how abhirup solved it
i m unable 2 understand it
@ gsns
just differentiate T3/V=k
i m too lazy 2 rite all the steps...
find
dV/VdT
T3/V=k
T3=kV
3T2 = k dV/dT
k=T3/V
substitute back
you will get the form of abhirup