If a,b,c are real, LHS≤0 and RHS≥0, so only solution is (0,0,0)
How LHS≤0?
take 1,2,3
we get lhs≥0
i am excited to see the solution:
(a-b)(b-c)(c-a)=a^{2}+b^{2}+c^{2}
i think latex is playing truant again. could u type it out using the editor?
If a,b,c are real, LHS≤0 and RHS≥0, so only solution is (0,0,0)
If a,b,c are real, LHS≤0 and RHS≥0, so only solution is (0,0,0)
How LHS≤0?
take 1,2,3
we get lhs≥0