466the opts. are :
(A)
- Himanshu Giria (A)99748
(B)98748
(C)96747
(D)97147
- Himanshu Giria there is no no. ending with 0 in any of the options ...
10 DISTINCT alphabetas are given.
5 letter words are to be formed .
no. of ways in which at least one allphabet is repeated . is :
-
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6 Answers
1133105 - 10C5.5!
- Himanshu Giria i too got this but this was not in the options only ... :)
Upvote·0· Reply ·2014-02-15 21:54:46
466
535is the answer given as (A)?
- Himanshu Giria Don't know it had come in this kurukshetra . but please tell how did you get it
535i just didn't multiply by 5!. so it became
105 - 10C5. what i was thinking was that it asks us to find the number of ways..hence that omission.
I am not sure about the method..
- Himanshu Giria but i didnt undrstnd y are'nt we multiplying by 5!
- Himanshu Giria that shud b included in no. of ways ......
466i m saying so bcos in 100000 we r already includung the extra arrangements(not only selections) so we again need to delete thode arrangments .......
- Aditya Agarwal here, no of ways or arranging is the same as no. of ways or choosing.
no. of ways of choosing a word. is 10^5
and so is the no. of arranging the letters.
- Himanshu Giria Hmmm .... Thanx :)