ok well its quite straight unless i am missing something
βsinβ + (Ï€/4)cosβ +√2β = Ï€/4∫β f(x)dx
which means
βcosβ + sinβ - (π/4)sinβ + √2 = f(β)
answer seems to be
(b) [1]
ok well its quite straight unless i am missing something
βsinβ + (Ï€/4)cosβ +√2β = Ï€/4∫β f(x)dx
which means
βcosβ + sinβ - (π/4)sinβ + √2 = f(β)
answer seems to be
(b) [1]
[339]
yar susti mein hoon
ek baar pad ke aaya nai to pooch lia
THANX 4 THE HELP