Limits.........

Evaluate lim [x ² / sin²x. cos x ] , where [ ]denotes the greatest integer functin
xâ†’0

5 Answers

is the ans 0

y!!

this is not that straight forward.. (sorry if i am already making a wrong assumption!)

I thnk this question needs a few things

Hint: check if derivative of sinx/√cosx near zero

is ans 1

i think ans would be 1

applying l hospital rule inside the box

we get the reduced expression as 1/cosx

now if x->0-
then it is 1/cos(-h)=1 hence the expression =1
otherwise also it is 1/cosh=1

hence answer =1

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

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