well then why not 'b' ?
i think i did some caculation me gadbadi...
Find all the values of m for which equation
(x2+x+1)2-(m-3)(x2+x+1)+m=0 (where m is a rel parameter) will have real roots
yup sky after some rough calculations i m getin smthing like b
din notice that b4
I knew that would happen Vishal
that's why I don prefer posting option