Solve this one

\int_{-2}^{2}{\frac{sin^2x}{[\frac{x}{\pi }]+0.5}}dx
where [.] =GINT

2 Answers

Denominator is an odd function , so the integral is 0.

consider f(x) = [x / pi] + 0.5

f(-x) = [-x /pi] + 0.5 = -1 - [x / pi] + 0.5 = -[x /pi] - 0.5

so, f(-x) = -f(x)

wow,.........ques finished in 1 sec...gr88

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