we get coordinates of parallelogram
now eqn. of AC IS y-1=(-4)x-3
eqn. of BD is y-1=4(x-2)
The equation to the pairs of opposite sides of a parallelogram are x2 – 5x + 6 = 0 and y2 – 6y + 5. Find the equations of its
diagonals.
we get coordinates of parallelogram
now eqn. of AC IS y-1=(-4)x-3
eqn. of BD is y-1=4(x-2)