Test:26 QNo:10

\hspace{-16}$So from figure Point $\mathbf{M\left(\frac{h+2}{2}\;,\frac{k+2}{2}\right)}$ lie on $\mathbf{3x+4y-5=0}$\\\\ So $\mathbf{3.\left(\frac{h+2}{2}\right)+4\left(\frac{k+2}{2}\right)-5=0}$\\\\ So $\mathbf{3h+6+4k+8-10=0\Leftrightarrow 3h+4k=-4..............(1)}$\\\\ Now $\mathbf{-\frac{3}{4}\times \left(\frac{k-2}{h-2}\right)=-1}$\\\\ $\mathbf{-3k+6=-4h+8\Leftrightarrow 4h-3k=2...............................(2)}$\\\\ Now solve These two equation....\\\\ $\mathbf{\left(h,k\right)=\left(-\frac{4}{25}\;,\frac{-22}{25}\right)}$

can we do it like dis??? take d point as (x,y) and find out its distance from d line. then find the distance of (2,2) from the same line. again d mid point of the line joining (2,2) and (x,y) will satisfy the equatio n given as it will lie on it. that is how i will solve it...

and the answer comes out to be (x,y)=(-4/25, -22/25)