Current Electricity-10

IIT JEE 2015 Tutorials › Electricity and magnetism questions › Current Electricity-10

#Physics #Electricity and magnetism

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4 Answers

229

Dwijaraj Paul Chowdhury ·2013-06-29 19:06:16

For each bulb....power =v²/r
:. r= v²/p
= 220*220/100 =484
Equivalent resistance(R) =4r/3
:.POWER = V²/R
=( 220*220*3) / (4*484)
= 75 watts

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229

Dwijaraj Paul Chowdhury ·2013-06-26 02:36:59

A)__75watts

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Akash Anand Good Work
Upvote·0· Reply ·2013-06-26 03:56:35
Akash Anand Try to post a crisp solution after 1/2 day so that other people can take a hint.
Upvote·0· Reply ·2013-06-26 22:50:14
Akash Anand Try to post a crisp solution after 1/2 day so that other people can take a hint.
Upvote·0· Reply ·2013-06-26 22:50:14
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Subhradeep Patra ·2013-06-26 03:23:37

D> 400/3 watts?

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Akash Anand Wrong..try again.
Upvote·0· Reply ·2013-06-26 03:56:22
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535

Aditya Agarwal ·2013-06-29 13:59:47

sir the solution?

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