1)

E vs x is constant.and E vs y is variable. when it is displaced perpendicular to the line line of charges
GUYS: the question im editing:
for 1st bit only..
E vs x for only when particle is displaced along line joining charges
E vx y for only when particle is displaced perpendicular to line joining charges
@ani: i want field vs. x or field vs. y not potential
@iitimcomin: if i slightly displace it perpendicularly, then it will keep on going to infinity naa.. i want THAT graph
thats more of a math question ........ bada complex equation aayegaa ........