11i know
yr 2nd ans is also correct
pls post the soln
11
Mani Pal Singh
·2009-02-25 09:54:55
mere ko ab tum bevakoof mat samjho !!!!!!!!!!!
give me proper explainations
39iii) a,b,cd aa raha hain. woh last wala dekhna hain........
11
Mani Pal Singh
·2009-02-25 09:37:58
YAAR DHYAAN SE DEKH ANS IS WRITTEN
ITS C AND A
106Q2. (ii) - (c)(a).... if voltmeter is attached in series then it has infinite resistance hence no current flows... but i dont know abt charge on capacitor maybe mathie can help... ya ya voltmeter reading will be 2V as well... uska jo side cell ke taraf hai us par potenial is 2V aur doosre taraf potential is 0V ... That's why no charge is developed on capacitor as well. as there is no pot. diff. across any end... both ends are at pot. zero.
11
Mani Pal Singh
·2009-02-25 02:40:00
sir ek baar isko bhi dekh lo
11
Mani Pal Singh
·2009-02-25 01:08:08
yaar apna ans to post kar de
11
Mani Pal Singh
·2009-02-23 20:09:47
mr iit please give the soln
ur ans is correct
11
Mani Pal Singh
·2009-02-23 08:51:07
ashish actually sara Q2 ek match matrix hai
give ur ans i will let u know later
106
Asish Mahapatra
·2009-02-23 08:49:01
manipal wat is answer of Q2b part iii?
3rest of it is beyod my syllabus!!!!!
3
iitimcomin
·2009-02-23 07:24:32
2. im gettin 3.5 as answer is it correct????
3
iitimcomin
·2009-02-23 07:07:03
to be presice 1.2909944487358697
3
iitimcomin
·2009-02-23 07:05:15
yep my answer is root(5/3) = 1.29 !!!!!!
3
iitimcomin
·2009-02-23 06:41:07
loop is fixed toh my ans. is rite otherwise its not!!!!!!
3
iitimcomin
·2009-02-23 06:39:24
prob no 3 ... at the topmost point if the net force is just zero it will complete the circle.....
or in other words mv2/2 = mg ............
or v= √2g ......(1) .........
conserving energy .......
1/2m(2g) + mg(4) = 1/2 mu2 .....
10mg = mu2 .........
u = √10g!!!!!
again 1/2mu2 = 1/2(k)x2...........
(10)mg = 3x2 ....
√5/3=x .... pardon calc. mistakes[1]
11
Mani Pal Singh
·2009-02-23 06:30:52
35 baande online and no attempts
please help
it will definitely help in jee
