now,
<v>2 = 0∫1V2t2dt + 1∫2(v/2)2 .dt
=><v>2 = v2/3 + v2/4 = 7v2/12
this is in 2secs.
in 1 sec,
<v>2 = 7v2/24
so <v> =√7v2/24 = v√7/24

the voltage time graph is shown. The rms value for the graph is
a)V
b)V/√2
c)V√(7/24)
d)V√(3/8)
now,
<v>2 = 0∫1V2t2dt + 1∫2(v/2)2 .dt
=><v>2 = v2/3 + v2/4 = 7v2/12
this is in 2secs.
in 1 sec,
<v>2 = 7v2/24
so <v> =√7v2/24 = v√7/24
[thanx .. i had forgottn this kinda questions.. ur q reminded me abt this afetr a long time :)]