1ya,i know C is Fe4[Fe(CN)6]3( PRUSSIAN BLUE) , but A is having Fe3+ cation but not the sulphate ion.second statement in the question is the confusing one
Q) (A)( yellow coloured solution ) changes to light green coloured solution (B), on passing H2S gas.
(A) and(B) both give white precipitate with BaCl2 solution, insoluble in conc. HCl . (A) gives blue
coloured precipitate (C) with K4[Fe(CN)6] ,but (B) does not. find (A),(B),(C).
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5 Answers
24both give white ppt with BaCl2 => SO42- is there in both
A gives blue colored ppt. with K4[Fe(CN)6] => Fe3+
=> A is Fe2(SO4)3
and C is Fe4[Fe(CN)6]
124My yesterday's view about BaCl2 test was biased with sulfates...but the reality is that sulphates,sulphites and chromates give the test
=> A is Fe2(SO4)3
or Fe2(SO3)3
or Fe2(CrO4)3
moreover Fe2(CrO4)3 is yellow in color..so A could be Iron(III) chromate[1]
1ya,eure.perhaps, u r right. actually,answer is given: A is FeCl3.but,i don't think its anyway near.i'm satisfied with ur answer.thnx,dude