3well can u explain y this rxn exist,but i have seen this in my buk,can u explain.
When SnCl2 is added to HgCl2 the substance formed is ?
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4 Answers
1when SnCl2 is added to HgCl2 , then a white precipitate of Hg2Cl2 is formed.
SnCl2 + HgCl2 → Hg2Cl2 + SnCl4.
if further SnCl2 is added, then a grey precipitate of Hg metal is obtained along with SnCl4.
these are the analysis confirmatory tests for Sn and Hg
31actually , when SnCl2 is added to HgCl2 , then Hg being at its highest oxidation state acts as oxidising agent and oxidises SnCl2 to SnCl4 and itself reduces to Hg2Cl2 i.e. the +1 oxidation state.
now,if this reaction of SnCl2 continues wid Hg2Cl2 , then Hg2Cl2 now gets reduced by SnCl2 to form metallic Hg and SnCl4 is also formed.