Since velocity is constant...so a force (friction force ) of magnitude mgsinα must act on block
so ne force=√(mgsinα)2+(mgcosα)2
A block moves down an incline with a constant velocity. What is the force exerted by the incline on the block ?
Since velocity is constant...so a force (friction force ) of magnitude mgsinα must act on block
so ne force=√(mgsinα)2+(mgcosα)2