1i meant find the relative acceleration of the block w.r.t the wedge along the slope.
aR+ a cosα= a .
aR = a(1-Cos α)
HOW TO GET THE ACCELERATION OF WEDGE "M"??
ASSUME ALL SURFACES FRICTIONLESS
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4 Answers
1'le the block move towards left with acceleration 'a'
now we can see that the block will slide in reference frame of the wedge with acceleration 'a-acosα'
let the Tension be T
mgsinα -T+maCosα = ma(1- cosα)
T = m(gsinα-a-2acosα)
now considering the wdge and block system only horizontal force is T .
thus T= (M+m) a
mgsinα - ma(1+2cosa) = Ma+am
=>a= mgsinαM +2m(1-cosα)
1now we can see that the block will slide in reference frame of the wedge with acceleration 'a-acosα' can u plzz explain this line a lil bit plzzzzzzzzzzzzzzzzzzzz
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