ABC is a triangle. The tangent to the circumcircle at A meets the line BC at D. The perpendicular to BC at B meets the perpendicular bisector of AB at E, and the perpendicular to BC at C meets the perpendicular bisector of AC at F. Show that D, E, F are collinear.
Please, post complete solution with figure.
PS- Sorry, but I dont know how to draw the image here.
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1 Answers
					
			Shubhodip
					·2011-11-13 06:35:08
			
			
		Dunnoh
posted http://www.artofproblemsolving.com/Forum/viewtopic.php?f=46&t=445381