1@ manmay..just use ideal gas eqn ....and keep diffentiatin'...kepin da reqd..constant...den multiply....u ll get da ans....A
For ideal gas PV=nRT, Z = PVnRT
for real gas (P + nav2)(V - nb)=nRT
Ideal gas can't be liquified by applying any pressure and temperature.
Q) For one mole of ideal gas (dPdT)v(dVdT)p(dVdP)T = ?
A) -R2P2 B)-RP2 C) -R2P D) -RP
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5 Answers
29for one mole of ideal gas PV=RT
so \frac{dP}{dT} = \frac{R}{V}
\frac{dV}{dT} = \frac{R}{P}
and since temp is constant.PdV + VdP = 0
so \frac{dV}{dP} = -\frac{V}{P}
on multiplying all of these u will get - \frac{R^{2}}{P^{2}}
So ans is A
1govind tera post clear nahin hai.Tera latex equation nahin aaya hai.
11arre manmay..isme kya samajh mein nahi aa raha hain??
govind ne jo likha hai..dats da ans....
RV*RP*-VP=-R2P2