Steam is passed over hot carbon to attain equilibrium at 400K
C(s) + H2O(g)<====>CO(g) +H2(g)
The eq constant is K=1.34 and total pressure of eq mixture is 200kPa.What are mole fractions of all substances at equilibrium
24I think we need to think in a fresh way..............Traditional method is not working
1for the answers given by eureka k is not dimensionless it is in atm and it is kp change 200kpa in atm and get the ans
1abhisheks:
ek aur physical http://targetiit.com/iit_jee_forum/posts/tricky_1901.html
:P
chem again
skygirl:
:P
dekhte hai
yeh asaan nahi hai kya ?
abhisheks:
trciky wala
?
skygirl:
haan
abhisheks:
but it is mentioned that K is dimensionless....
"
.....eureka
i don know how
skygirl:
dhutt K ka dim rahega
pakka rahega
abhisheks:
haan
mera design wla post ka eq dekho to wahi hai naa
*3rd reply
Sent at 20:33 on Friday
skygirl:
haan wahi hai
33is this the answer
mole fraction of..
CO is 0.0025
H2 is 0.0025
H20 is .995
[7]
24let me give u the answers
mole fractionCO=mole fractionH2=0.38
mole fractionH2O=0.22
33dimensionless??
how can this be...
but solving above two eqns give answer or not ?
33â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘
if its Kp then...
P2/PH2O=Kp
2P+PH2O=200KPa..
â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘â–’â–‘
24nothing is given.........but it is mentioned that K is dimensionless.....(forgot to write )