62
Lokesh Verma
·2009-07-23 02:36:26

Now can you see the thing
try to figure and solve it..
If you cant, then ask :)
1
Akand
·2009-07-23 02:37:44
solved in sum paper................

1
Akand
·2009-07-23 02:38:42
waaaaaaaaahhhhhhhhhh......sorry for posting............u shud hav practised urself.........
1
Abhisekh Mukherjee
·2009-08-04 01:13:43

let the width of the lake be x
α and β are the angle
tanα=H/x
x=H/tanα
tanβ=2h+H/x
x=2h+H/tanβ=2h/tanβ+H/tanβ
Htanα=Htanβ+2htanβ
H(1tanα-tanβ)=2htanβ
now solving we get H
then we add +h on both sides and we get the result
H+h=2htanα/tanβ-tanα+h
=h(tanα+tanβ)/(tanα-tanβ)