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		Proof that (tan5A+tan3A)/(tan5A-tan3A)=4cos4Acos2A ... 
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		Help me with this. I need it urgently. And I want full solution ... 
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		If Tan A/2 = (Tan B/2)3 and Tan B = 2 Tan C then find (A + B)\C. ... 
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		If sin α + sin β = a and cos α + cos β = b,then prove that sin(α + β) = (2ab/a2 + b2) ... 
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		if α,β are two different values of θ lying between 0 and 2Πwhich satisfy the equation 6 cos θ + 8 sin θ = 9,then find the value of sin(α + β). ... 
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		If angle θ is divided into two parts such that the tangent of one part is λ times the tangent of the other, and α is their difference,show that sinθ = (λ+1/λ-1)sinα ... 
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		Can anyone tell me where I can download the solutions to R.D. Sharma in pdf format? Thanks in advance. Please post the complete link. ... 
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		If cosθ=ncos(θ+2α)then show that (n+1)tan(θ+α)=(n-1)cotα ... 
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		Prove that : CotA + Cot(60+a) - Cot(60 -a) = 3Cot3A ... 
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		Prove that: TanA + Tan(60+a) - Tan(60 -a) = 3Tan3A ... 
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		the positive values of a for which the equation [x+a]=sin(Ï€x/2) will have no solution is,where [.] denotes greatest integer function- a) (0,1); b)(1,2);c) (0,2);d) NOT. ... 
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		If cos(α-β)+cos(β-γ)+cos(γ-α)= -3/2 , then p.t. → cosα +cosβ +cosγ =sinα +sinβ +sinγ =0 . ... 
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		If tan(inverse)(x+2/x)-tan(inverse)4/x-tan(inverse)(x-2/x)=0 then x=............ y=........... (M.L.Khanna Page 464 Problem No.37a) ... 
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		Write the following function in the simplest form :- tan_1√ 1-x/1+x ... 
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		Prove that sin2θ=(x+y)2/4xy possible for real values of x and y only when x is equal to y. x not equal to 0. ... 
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		Prove that tan 8θ -tan 6θ- tan 2θ = tan 8θ tan 6θtan 2θ ... 
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		If tan2θ = 1-k2,s.t. sec2θ+tan3θ cosecθ = (2-k2)3/2 ... 
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		A+B+C= Î /2 p.t. +cos2A+cos2B+cos2C=2(1+sinAsinBsinC) ... 
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		cosec θ = cot θ + √3 ...