Test:13 QNo:10

JEE Mains 2015 Coaching › Disucss Test Questions questions › Test:13 QNo:10

a is chosen as a random natural number. what is the probability that (x-1)(x-10)(x-a) has no repeated roots?

#Miscellaneous #Disucss Test Questions

UP 0 DOWN 0 0 5
Post on FacebookPost anonymously?

5 Answers

sridharm chandra ·2009-12-07 04:37:22

probability cannot be dtermined

UP 0 DOWN 0
Post on FacebookPost anonymously?

sridharm chandra ·2009-12-07 04:38:55

savandi

UP 0 DOWN 0
Post on FacebookPost anonymously?

cute_cat ·2010-05-27 00:37:41

can someone explain???

UP 0 DOWN 0
Post on FacebookPost anonymously?

Pritish Chakraborty ·2010-05-27 19:45:45

No repeated roots as in....a cannot be 1 or 10, isn't it?
There are n natural numbers. Probability that a is 1 or 10
= P(1 or 10)
= P(1) + P(10)
= 1/n + 1/n
= 2/n

So probability that a is not 1 or 10 is given by
P(Not 1 or 10)
= n - 2n

UP 0 DOWN 0
Post on FacebookPost anonymously?

rishicomplex ad ·2010-12-06 22:31:49

answer should be 1 their ans is rong

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Test:13 QNo:10

5 Answers

Your Answer

Add Image

Similar Questions