11st of all x cannot be negative as all the terms become +ve.
Morover, x cannot be <1 (obvious, isn't it?)
So, x≥1
Now, The inequality x2-x+2≤0 is satisfied for 1≤x≤2
So, the given inequality will be satisfied for a subset of [1,2]
It is apparent that for x≥√2 the given inequality is not satisfied.
So x ε [1,√2)
1The soln given for this question is absolutely wrong.
soln is x ε [1,√2).
hence answer shud b none of these option d.
1@apoorv
ya it happens some time.....
1
rohit007 joshi
·2010-04-28 10:04:22
solution of last question is wrong
1
mkagenius
·2010-05-26 22:38:11
give me my 100 percent marks :(((((
:(((((((((((((((((((((((((((((((((((((((((((((((
:((((((((((((((((((((((((((((((((((((((((((
1
sivapoornan
·2011-12-03 19:18:24
the correct solution is [1,√3)