Test:335 QNo:63

NH3(g)+3Cl2(g)→NCl3(g)+3HCl(g) ΔH1=-55 kJ
N2(g)+3H2(g)→2NH3(g)+24 kJ
H2(g)+Cl2(g)→2HCl(g) ΔH3=36 kJ

The heat of formation of NCl3(g) is

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