Test:351 QNo:53

The centre of the smallest circle containing the circles x2+y2=4 and (x-8)2+y2=16 is

5 Answers

1
Philip Calvert ·

it should be (5,0)

why (7,0) ???

dist of 7,0 from 12,0 is 5 whereas
from -2,0 it is 7 so how come it is the midpoint !!

11
Subash ·

@mani the last point that you have marked shouldnt it be (12,0)

as the radius is 4?

And the midpoint should be found with (-2,0) and (12,0)

I agree with philip shouldnt ans be (5,0)

11
Mani Pal Singh ·

sorry bro

1
sriraghav ·

yes... both hav to touch the diametrically opposite ends of the circle required*wit centre 5.,0

1357
Manish Shankar ·

Yup the answer is (5,0)

chhoti chhoti galtiyan sabse hoti hai :P

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